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Bhulu Aich
Bhulu AichExclusive Author
Asked: April 5, 2024In: SSC Maths

The sum of three consecutive odd numbers is 1383 . What is the largest number? (a) 463 (b) 49 (c) 457 (d) 461 (e) None of these

The sum of three consecutive odd numbers is 1383 . What is the largest number? (a) 463 (b) 49 (c) 457 (d) 461 (e) None of these

SSC CGLSSC Maths Practice Questions with Solution
  1. Abstract Classes Power Elite Author
    Added an answer on April 5, 2024 at 5:16 pm

    To find the three consecutive odd numbers whose sum is 1383, let's denote the smallest of these numbers as \(n\), the next one as \(n + 2\), and the largest as \(n + 4\) (since odd numbers differ by 2). The sum of these numbers is given as: \[n + (n + 2) + (n + 4) = 1383\] Simplifying, we get: \[3nRead more

    To find the three consecutive odd numbers whose sum is 1383, let’s denote the smallest of these numbers as \(n\), the next one as \(n + 2\), and the largest as \(n + 4\) (since odd numbers differ by 2).

    The sum of these numbers is given as:
    \[n + (n + 2) + (n + 4) = 1383\]

    Simplifying, we get:
    \[3n + 6 = 1383\]

    Subtracting 6 from both sides:
    \[3n = 1377\]

    Dividing by 3:
    \[n = 459\]

    So, the three consecutive odd numbers are 459, 461, and 463. The largest number among them is \(463\).

    Therefore, the correct answer is (a) 463.

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Bhulu Aich
Bhulu AichExclusive Author
Asked: April 5, 2024In: SSC Maths

If \(\frac{a+b}{b+c}=\frac{c+d}{d+a}\), then (a) \(a\) must equal \(c\) (b) \(a+b+c+d\) must equal zero (c) either \(a=c\) or \(a+b+c+d=0\), or both (d) \(a(b+c+d)=c(a+b+d)\)

If (a) (a+b)/(b+c)=(c+d)/(d+a), then (b) a+b+c+d must equal zero (c) either a=c or a+b+c+d=0, or both (d) a(b+c+d)=c(a+b+d)

SSC CGLSSC Maths Practice Questions with Solution
  1. Abstract Classes Power Elite Author
    Added an answer on April 5, 2024 at 3:17 pm

    Starting from the given proportional relationship: \[ \frac{a+b}{b+c} = \frac{c+d}{d+a} \] Multiplying across to eliminate the denominators, we have: \[ (a + b)(d + a) = (b + c)(c + d) \] Expanding both sides: \[ ad + a^2 + bd + ab = bc + c^2 + cd + bd \] Rearranging to group like terms: \[ a^2 - c^Read more

    Starting from the given proportional relationship:

    \[
    \frac{a+b}{b+c} = \frac{c+d}{d+a}
    \]

    Multiplying across to eliminate the denominators, we have:

    \[
    (a + b)(d + a) = (b + c)(c + d)
    \]

    Expanding both sides:

    \[
    ad + a^2 + bd + ab = bc + c^2 + cd + bd
    \]

    Rearranging to group like terms:

    \[
    a^2 – c^2 + ad – cd + ab – bc = 0
    \]

    Factoring by grouping, where appropriate, using the difference of squares for \(a^2 – c^2\) and factoring out the common terms in the other parts:

    \[
    (a – c)(a + c) + (a – c)d + (a – c)b = 0
    \]

    Factoring \(a – c\) from each term:

    \[
    (a – c)(a + c + d + b) = 0
    \]

    For this product to equal zero, at least one of the factors must be zero. Therefore:

    \[
    a – c = 0 \quad \text{or} \quad a + b + c + d = 0
    \]

    This means:

    – \(a = c\), or
    – \(a + b + c + d = 0\), or
    – Both conditions could be true in certain scenarios.

    Therefore, the correct interpretation is option (c) either \(a = c\) or \(a+b+c+d = 0\), or both.

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Bhulu Aich
Bhulu AichExclusive Author
Asked: April 5, 2024In: SSC Maths

If \(5 \sqrt{5} \times 5^{3} \div 5^{-3 / 2}=5^{(a+2)}\), then value of \(a\) is

If 5 * sqrt(5) * 5^3 / 5^(-3/2) = 5^(a+2), then the value of a is

SSC CGLSSC Maths Practice Questions with Solution
  1. Abstract Classes Power Elite Author
    Added an answer on April 5, 2024 at 2:29 pm

    Given the equation: \[ 5 \sqrt{5} \times 5^3 \div 5^{-3 / 2} = 5^{(a+2)} \] We start by expressing all terms as powers of 5: \[ 5^1 \times 5^{\frac{1}{2}} \times 5^3 \div 5^{-\frac{3}{2}} = 5^{a+2} \] When you combine the exponents, you add them: \[ 5^{1 + \frac{1}{2} + 3} \times 5^{\frac{3}{2}} = 5Read more

    Given the equation:

    \[
    5 \sqrt{5} \times 5^3 \div 5^{-3 / 2} = 5^{(a+2)}
    \]

    We start by expressing all terms as powers of 5:

    \[
    5^1 \times 5^{\frac{1}{2}} \times 5^3 \div 5^{-\frac{3}{2}} = 5^{a+2}
    \]

    When you combine the exponents, you add them:

    \[
    5^{1 + \frac{1}{2} + 3} \times 5^{\frac{3}{2}} = 5^{a+2}
    \]

    Since multiplying with the same base allows you to add exponents:

    \[
    5^{\frac{2}{2} + \frac{1}{2} + \frac{6}{2} + \frac{3}{2}} = 5^{a+2}
    \]

    Simplify the exponents:

    \[
    5^{\frac{12}{2}} = 5^{a+2}
    \]

    Which simplifies further to:

    \[
    5^6 = 5^{a+2}
    \]

    Setting the exponents equal to each other gives us:

    \[
    a+2 = 6
    \]

    Solving for \(a\):

    \[
    a = 6 – 2
    \]
    \[
    a = 4
    \]

    Therefore, the value of \(a\) is \(\boldsymbol{4}\).

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Bhulu Aich
Bhulu AichExclusive Author
Asked: April 5, 2024In: SSC Maths

If \(x^{*} y=x^{2}+y^{2}-x y\), then value of \(9^{*} 11\) is

If x * y = x^2 + y^2 – xy, then the value of 9 * 11 is

SSC CGLSSC Maths Practice Questions with Solution
  1. Abstract Classes Power Elite Author
    Added an answer on April 5, 2024 at 2:17 pm

    Given the operation \(x^{*} y = x^{2} + y^{2} - xy\), let's calculate the value of \(9^{*} 11\). Substitute \(x = 9\) and \(y = 11\) into the formula: \[ 9^{*} 11 = 9^{2} + 11^{2} - 9 \times 11 \] Simplify each term: \[ 9^{*} 11 = 81 + 121 - 99 \] Add and subtract the terms: \[ 9^{*} 11 = 202 - 99 =Read more

    Given the operation \(x^{*} y = x^{2} + y^{2} – xy\), let’s calculate the value of \(9^{*} 11\).

    Substitute \(x = 9\) and \(y = 11\) into the formula:

    \[
    9^{*} 11 = 9^{2} + 11^{2} – 9 \times 11
    \]

    Simplify each term:

    \[
    9^{*} 11 = 81 + 121 – 99
    \]

    Add and subtract the terms:

    \[
    9^{*} 11 = 202 – 99 = 103
    \]

    Therefore, the value of \(9^{*} 11\) is \(\boldsymbol{103}\).

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Bhulu Aich
Bhulu AichExclusive Author
Asked: April 5, 2024In: SSC Maths

Simplify: \(5 \sqrt[3]{250}+7 \sqrt[3]{16}-14 \sqrt[3]{54}\).

Simplify: `5*root(3,250) + 7*root(3,16) – 14*root(3,54)`.

SSC CGLSSC Maths Practice Questions with Solution
  1. Abstract Classes Power Elite Author
    Added an answer on April 5, 2024 at 1:18 pm

    To simplify the expression \(5 \sqrt[3]{250} + 7 \sqrt[3]{16} - 14 \sqrt[3]{54}\), we first break down each term under the cube root into its prime factors or into a product that makes it easier to take out cube roots. Simplification Steps 1. Break down each number under the cube root into a productRead more

    To simplify the expression \(5 \sqrt[3]{250} + 7 \sqrt[3]{16} – 14 \sqrt[3]{54}\), we first break down each term under the cube root into its prime factors or into a product that makes it easier to take out cube roots.

    Simplification Steps

    1. Break down each number under the cube root into a product of numbers that includes a perfect cube when possible:
    – \(250 = 5^3 \times 2\)
    – \(16 = 2^4\)
    – \(54 = 2 \times 3^3\)

    2. Rewrite the expression with these factors:
    – \(5 \sqrt[3]{5^3 \times 2} + 7 \sqrt[3]{2^4} – 14 \sqrt[3]{2 \times 3^3}\)

    3. Simplify each term:
    – For \(5 \sqrt[3]{5^3 \times 2}\), the cube root of \(5^3\) is 5, so this becomes \(5 \times 5 \sqrt[3]{2}\) or \(25 \sqrt[3]{2}\).
    – For \(7 \sqrt[3]{2^4}\), note that \(2^4\) is \(2^3 \times 2\), so the cube root of \(2^3\) is 2, leading to \(7 \times 2 \sqrt[3]{2}\) or \(14 \sqrt[3]{2}\).
    – For \(14 \sqrt[3]{2 \times 3^3}\), the cube root of \(3^3\) is 3, so this becomes \(14 \times 3 \sqrt[3]{2}\) or \(42 \sqrt[3]{2}\).

    4. Putting it all together:
    – \(25 \sqrt[3]{2} + 14 \sqrt[3]{2} – 42 \sqrt[3]{2}\)

    5. Combine like terms:
    – \(25 \sqrt[3]{2} + 14 \sqrt[3]{2} – 42 \sqrt[3]{2} = (25 + 14 – 42) \sqrt[3]{2}\)
    – \(= -3 \sqrt[3]{2}\)

    Therefore, the simplified form of \(5 \sqrt[3]{250} + 7 \sqrt[3]{16} – 14 \sqrt[3]{54}\) is \(-3 \sqrt[3]{2}\).

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Bhulu Aich
Bhulu AichExclusive Author
Asked: April 5, 2024In: SSC Maths

The minimum value of the expression \(|17 x-8|-9\) is (a) 0 (b) -9 (c) \(\frac{8}{17}\) (d) none of these

The minimum value of the expression \(|17 x-8|-9\) is (a) 0 (b) -9 (c) \(\frac{8}{17}\) (d) none of these

SSC CGLSSC Maths Practice Questions with Solution
  1. Abstract Classes Power Elite Author
    Added an answer on April 5, 2024 at 12:21 pm

    The expression \(|17x - 8| - 9\) represents the distance of \(17x - 8\) from 0 on the number line, minus 9. The minimum value of the absolute value function \(|17x - 8|\) is 0, which occurs when \(17x - 8 = 0\) or \(x = \frac{8}{17}\). Since the absolute value function cannot be negative, the minimuRead more

    The expression \(|17x – 8| – 9\) represents the distance of \(17x – 8\) from 0 on the number line, minus 9. The minimum value of the absolute value function \(|17x – 8|\) is 0, which occurs when \(17x – 8 = 0\) or \(x = \frac{8}{17}\).

    Since the absolute value function cannot be negative, the minimum value of \(|17x – 8|\) is 0. Therefore, the minimum value of the entire expression \(|17x – 8| – 9\) is \(0 – 9 = -9\).

    Thus, the correct answer is (b) -9.

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Bhulu Aich
Bhulu AichExclusive Author
Asked: April 5, 2024In: SSC Maths

The value of the numeral MCDLXIV is: (a) 1666 (b) 664 (c) 1464 (d) 656

The value of the numeral MCDLXIV is: (a) 1666 (b) 664 (c) 1464 (d) 656

SSC CGLSSC Maths Practice Questions with Solution
  1. Abstract Classes Power Elite Author
    Added an answer on April 5, 2024 at 12:17 pm

    To find the value of the Roman numeral MCDLXIV, we can break it down into its components: - M = 1000 - CD = 400 (500 - 100) - LX = 60 (50 + 10) - IV = 4 (5 - 1) Adding these values together, we get: 1000 + 400 + 60 + 4 = 1464 Therefore, the value of the numeral MCDLXIV is 1464, which corresponds toRead more

    To find the value of the Roman numeral MCDLXIV, we can break it down into its components:

    – M = 1000
    – CD = 400 (500 – 100)
    – LX = 60 (50 + 10)
    – IV = 4 (5 – 1)

    Adding these values together, we get:

    1000 + 400 + 60 + 4 = 1464

    Therefore, the value of the numeral MCDLXIV is 1464, which corresponds to option (c) 1464.

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Bhulu Aich
Bhulu AichExclusive Author
Asked: April 4, 2024In: SSC Maths

A cube of side 11 cm is melted and converted into a solid cylinder. It is found that the height of the cylinder so formed is 7 times the length of the rectangle whose width is 1.5 cm and perimeter 4 cm. Find the radius of the cylinder?

A cube of side 11 cm is melted and converted into a solid cylinder. It is found that the height of the cylinder so formed is 7 times the length of the rectangle whose width is 1.5 cm and perimeter ...

SSC CGLSSC Maths Practice Questions with Solution
  1. Abstract Classes Power Elite Author
    Added an answer on April 4, 2024 at 3:46 pm

    Let's break this down step by step: 1. Volume of the Cube : The volume of a cube is given by \( \text{Volume} = a^3 \), where \( a \) is the side length of the cube. Here, \( a = 11 \) cm. So, the volume of the cube is \( 11^3 \) cubic cm. 2. Volume of the Cylinder : The volume of a cylinder is giveRead more

    Let’s break this down step by step:

    1. Volume of the Cube : The volume of a cube is given by \( \text{Volume} = a^3 \), where \( a \) is the side length of the cube. Here, \( a = 11 \) cm. So, the volume of the cube is \( 11^3 \) cubic cm.

    2. Volume of the Cylinder : The volume of a cylinder is given by \( \text{Volume} = \pi r^2 h \), where \( r \) is the radius and \( h \) is the height. We are given that the height of the cylinder is 7 times the length of the rectangle. The length of the rectangle is not explicitly given, but we can find it using the given information about the width and perimeter of the rectangle.

    3. Finding the Length of the Rectangle : The perimeter of a rectangle is given by \( 2(l + w) \), where \( l \) is the length and \( w \) is the width. We are given that the width \( w = 1.5 \) cm and the perimeter is 4 cm. Therefore, \( 2(l + 1.5) = 4 \). Solving for \( l \), we get \( l = \frac{4}{2} – 1.5 = 0.5 \) cm.

    4. Height of the Cylinder : Since the height of the cylinder is 7 times the length of the rectangle, the height is \( 7 \times 0.5 = 3.5 \) cm.

    5. Volume of the Cylinder (Continued) : Now that we have the height of the cylinder as 3.5 cm, we can find its volume using the formula \( \pi r^2 h \).

    6. Equating Volumes : Since the cube is melted to form the cylinder, the volume of the cube should be equal to the volume of the cylinder. Setting these two volumes equal to each other, we can solve for the radius \( r \) of the cylinder.

    Let’s calculate the radius \( r \) of the cylinder using the given information.

    Given:
    Side length of cube, \(a = 11\) cm
    Width of rectangle, \(w = 1.5\) cm
    Perimeter of rectangle, \(P = 4\) cm

    1. Volume of Cube : \(V_{\text{cube}} = a^3 = 11^3\) cm³.

    2. Length of Rectangle : Perimeter of rectangle, \(P = 2(l + w)\). We have \(P = 4\) and \(w = 1.5\). Solve for \(l\):

    \[4 = 2(l + 1.5) \]
    \[2 = l + 1.5 \]
    \[l = 0.5\] cm.

    3. Height of Cylinder : Height of cylinder, \(h = 7l = 7 \times 0.5\) cm.

    4. Volume of Cylinder : Volume of cylinder, \(V_{\text{cylinder}} = \pi r^2 h\).

    Since the cube is melted and converted into the cylinder, their volumes are equal:

    \[11^3 = \pi r^2 \times 7 \times 0.5\]

    \[1331 = 3.5 \pi r^2\]

    \[r^2 = \frac{1331}{3.5\pi}\]

    \[r = \sqrt{\frac{1331}{3.5\pi}}\]

    To find the radius of the cylinder, we first calculate the value inside the square root:

    \[ r = \sqrt{\frac{1331}{3.5\pi}} \]

    \[ r = \sqrt{\frac{1331}{3.5 \times 3.14159}} \]

    \[ r = \sqrt{\frac{1331}{10.99265}} \]

    \[ r = \sqrt{121} \]

    \[ r = 11 \text{ cm} \]

    Therefore, the radius of the cylinder is 11 cm.

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Bhulu Aich
Bhulu AichExclusive Author
Asked: April 4, 2024In: SSC Maths

A sum of money triples itself in 7 years. In how many years it amounts to 9 times of itself, if the interest is compounded annually?

A sum of money triples itself in 7 years. In how many years it amounts to 9 times of itself, if the interest is compounded annually?

SSC CGLSSC Maths Practice Questions with Solution
  1. Abstract Classes Power Elite Author
    Added an answer on April 4, 2024 at 3:24 pm

    Let's denote the principal amount as \(P\) and the interest rate as \(r\) (expressed as a decimal). Given: - The money triples itself in 7 years. This means that the amount \(A\) after 7 years is \(3P\). - The interest is compounded annually. The formula for compound interest is: \[ A = P(1 + r)^t \Read more

    Let’s denote the principal amount as \(P\) and the interest rate as \(r\) (expressed as a decimal).

    Given:
    – The money triples itself in 7 years. This means that the amount \(A\) after 7 years is \(3P\).
    – The interest is compounded annually.

    The formula for compound interest is:
    \[ A = P(1 + r)^t \]
    where \(A\) is the amount after \(t\) years, \(P\) is the principal, \(r\) is the interest rate, and \(t\) is the time in years.

    From the given information, we have:
    \[ 3P = P(1 + r)^7 \]
    \[ 3 = (1 + r)^7 \]
    \[ (1 + r) = \sqrt[7]{3} \]

    Now, we need to find the time \(t\) when the amount becomes 9 times of itself:
    \[ 9P = P(1 + r)^t \]
    \[ 9 = (1 + r)^t \]
    \[ 9 = (\sqrt[7]{3})^t \]
    \[ 9 = 3^{\frac{t}{7}} \]
    \[ 3^2 = 3^{\frac{t}{7}} \]
    \[ 2 = \frac{t}{7} \]
    \[ t = 14 \]

    Conclusion

    The money will amount to 9 times of itself in 14 years if the interest is compounded annually.

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Bhulu Aich
Bhulu AichExclusive Author
Asked: April 4, 2024In: SSC Maths

The length of the sides of a triangle are 9 cm, 12 cm and 15 cm. Find the length of the perpendicular from the opposite vertex to the side whose length is 15 cm.

The length of the sides of a triangle are 9 cm, 12 cm and 15 cm. Find the length of the perpendicular from the opposite vertex to the side whose length is 15 cm.

SSC CGLSSC Maths Practice Questions with Solution
  1. Abstract Classes Power Elite Author
    Added an answer on April 4, 2024 at 2:54 pm

    Solution Given: - The lengths of the sides of the triangle are 9 cm, 12 cm, and 15 cm. We can use Heron's formula to find the area of the triangle and then use the area to find the length of the perpendicular from the opposite vertex to the side of length 15 cm. Step 1: Calculate the semi-perimeterRead more

    Solution

    Given:
    – The lengths of the sides of the triangle are 9 cm, 12 cm, and 15 cm.

    We can use Heron’s formula to find the area of the triangle and then use the area to find the length of the perpendicular from the opposite vertex to the side of length 15 cm.

    Step 1: Calculate the semi-perimeter (s) of the triangle

    \[ s = \frac{9 + 12 + 15}{2} = 18 \text{ cm} \]

    Step 2: Use Heron’s formula to find the area (A) of the triangle

    \[ A = \sqrt{s(s – 9)(s – 12)(s – 15)} \]
    \[ A = \sqrt{18(18 – 9)(18 – 12)(18 – 15)} \]
    \[ A = \sqrt{18 \times 9 \times 6 \times 3} \]
    \[ A = \sqrt{2916} \]
    \[ A = 54 \text{ cm}^2 \]

    Step 3: Find the length of the perpendicular (h) from the opposite vertex to the side of length 15 cm

    Using the formula for the area of a triangle (\(A = \frac{1}{2} \times \text{base} \times \text{height}\)):
    \[ 54 = \frac{1}{2} \times 15 \times h \]
    \[ h = \frac{54 \times 2}{15} \]
    \[ h = \frac{108}{15} \]
    \[ h = 7.2 \text{ cm} \]

    Conclusion

    The length of the perpendicular from the opposite vertex to the side whose length is 15 cm is 7.2 cm.

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Abstract Classes

Abstract Classes

Abstract Classes is a dynamic educational platform designed to foster a community of inquiry and learning. As a dedicated social questions & answers engine, we aim to establish a thriving network where students can connect with experts and peers to exchange knowledge, solve problems, and enhance their understanding on a wide range of subjects.

About Us

  • Meet Our Team
  • Contact Us
  • About Us

Legal Terms

  • Privacy Policy
  • Community Guidelines
  • Terms of Service
  • FAQ (Frequently Asked Questions)

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