Find the value of `16/sqrt(3) * (cos(50) * cos(10) * cos(110) * cos(60))`.
Let's calculate the percentage of land that the man can purchase with Rs. 2,50,000. First, we'll find out the total cost of the land: Total cost of the land = Area of the land × Rate per square metre = 10,000 m² × Rs. 2000/m² = Rs. 2,00,00,000 Now, the man has Rs. 2,50,000 with him. The percentage oRead more
Let’s calculate the percentage of land that the man can purchase with Rs. 2,50,000.
First, we’ll find out the total cost of the land:
Total cost of the land = Area of the land × Rate per square metre
= 10,000 m² × Rs. 2000/m²
= Rs. 2,00,00,000
Now, the man has Rs. 2,50,000 with him. The percentage of the land he can purchase with this amount is:
Percentage of land = (Amount he has / Total cost of the land) × 100
= (2,50,000 / 2,00,00,000) × 100
= 0.0125 × 100
= 1.25%
Therefore, the man can purchase 1.25% of the land with Rs. 2,50,000.
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Given: - We need to find the value of \(\frac{16}{\sqrt{3}}\left(\cos 50^\circ \cos 10^\circ \cos 110^\circ \cos 60^\circ\right)\). 1. We use the identity \(\cos x \cos(60 - x) \cos(60 + x) = \frac{1}{4} \cos 3x\): \[ \cos x \cos(60 - x) \cos(60 + x) = \frac{1}{4} \cos 3x \] 2. Applying this identitRead more
Given:
– We need to find the value of \(\frac{16}{\sqrt{3}}\left(\cos 50^\circ \cos 10^\circ \cos 110^\circ \cos 60^\circ\right)\).
1. We use the identity \(\cos x \cos(60 – x) \cos(60 + x) = \frac{1}{4} \cos 3x\):
\[ \cos x \cos(60 – x) \cos(60 + x) = \frac{1}{4} \cos 3x \]
2. Applying this identity to \(\cos 50^\circ, \cos 10^\circ, \cos 110^\circ\):
\[ \cos 50^\circ \cos 10^\circ \cos 110^\circ = \frac{1}{4} \cos 150^\circ \]
\[ \cos 150^\circ = -\frac{\sqrt{3}}{2} \]
\[ \cos 50^\circ \cos 10^\circ \cos 110^\circ = -\frac{\sqrt{3}}{8} \]
3. Also, \(\cos 60^\circ = \frac{1}{2}\).
4. Substituting these values into the given expression:
\[ \frac{16}{\sqrt{3}}\left(\cos 50^\circ \cos 10^\circ \cos 110^\circ \cos 60^\circ\right) \]
\[ = \frac{16}{\sqrt{3}} \times \left(-\frac{\sqrt{3}}{8}\right) \times \frac{1}{2} \]
\[ = -1 \]
Conclusion:
See lessThe value of \(\frac{16}{\sqrt{3}}\left(\cos 50^\circ \cos 10^\circ \cos 110^\circ \cos 60^\circ\right)\) is \(-1\).