Last year my age was a perfect square number. Next year it will be a cubic number. What is my present age? (a) 25 years (b) 27 years (c) 26 years (d) 24 years
\[ \text { Solution: } \begin{aligned} {[5-} & \{6-(5-\overline{4-3})\}] \text { of } \frac{1+\frac{1}{2}}{1-\frac{1}{2}} \div \frac{\frac{1}{2}+\frac{1}{3}}{\frac{1}{2}-\frac{1}{3}} \\ & =[5-\{6-(5-1)\}] \text { of } \frac{\frac{3}{2}}{\frac{1}{2}} \sqrt{\frac{6}{6}} \\ & =\{5-(6-4)\} \Read more
\[
\text { Solution: } \begin{aligned}
{[5-} & \{6-(5-\overline{4-3})\}] \text { of } \frac{1+\frac{1}{2}}{1-\frac{1}{2}} \div \frac{\frac{1}{2}+\frac{1}{3}}{\frac{1}{2}-\frac{1}{3}} \\
& =[5-\{6-(5-1)\}] \text { of } \frac{\frac{3}{2}}{\frac{1}{2}} \sqrt{\frac{6}{6}} \\
& =\{5-(6-4)\} \text { of }\left(\frac{3}{2} \times \frac{2}{1}\right) \div\left(\frac{5}{6} \times \frac{6}{1}\right) \\
& =(5-2) \text { of } 3 \div 5 \\
& =3 \text { of } 3 \div 5=3 \times \frac{3}{5}=\frac{9}{5}
\end{aligned}
\]
Finding the Present Age Based on Mathematical Properties Given the intriguing conditions about the nature of one's age in relation to mathematical figures: Stated Conditions: The age last year was a perfect square number. The age next year will be a cubic number. Evaluation of Options: Considering tRead more
Finding the Present Age Based on Mathematical Properties
Given the intriguing conditions about the nature of one’s age in relation to mathematical figures:
Stated Conditions:
Evaluation of Options:
Considering the options provided and applying the given conditions to each, we meticulously analyze to find the correct age:
– Option (a) 25 years: Not viable, as 24 (last year) is not a perfect square and 26 (next year) is not a cube.
– Option (b) 27 years: Not viable, as 26 (last year) is not a perfect square and 28 (next year) is not a cube.
– Option (c) 26 years: This is the correct choice. If the present age is 26, then:
– Last year’s age was 25 (\(5^2\)), a perfect square.
– Next year’s age will be 27 (\(3^3\)), a perfect cube.
– Option (d) 24 years: Not viable, as 23 (last year) is not a perfect square and 25 (next year) is not a cube.
Correct Answer:
The logical deduction based on the conditions clearly points to Option (c) 26 years as the present age. At 26 years old:
Conclusion:
The individual’s current age, which perfectly transitions from a perfect square to a cubic number, is unequivocally 26 years. This finding not only satisfies the unique mathematical conditions presented but also underscores the harmonious relationship between sequential numerical properties and real-life scenarios.
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