For the following data, compute the range and standard deviation: 81, 32, 61, 72, 74, 75, 76, 71, 84, 85.
Compute range and standard deviation for the following data : 81, 32, 61, 72, 74, 75, 76, 71, 84, 85.
Share
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
1. Introduction
In this task, we will compute the range and standard deviation for the given dataset.
2. Range Calculation
The range is the difference between the highest and lowest values in a dataset. It provides a measure of the spread or variability of the data.
First, let's arrange the data in ascending order:
32, 61, 71, 72, 74, 75, 76, 81, 84, 85
The lowest value is 32, and the highest value is 85.
Range = Highest value – Lowest value
Range = 85 – 32
Range = 53
Therefore, the range of the given dataset is 53.
3. Standard Deviation Calculation
The standard deviation measures the dispersion or spread of data points around the mean. It indicates the average deviation of individual data points from the mean.
The formula for calculating the standard deviation (σ) is:
[ \sigma = \sqrt{\frac{\sum{(X – \bar{X})^2}}{N}} ]
Where:
First, let's calculate the mean ( ( \bar{X} ) ) of the dataset:
[ \bar{X} = \frac{81 + 32 + 61 + 72 + 74 + 75 + 76 + 71 + 84 + 85}{10} ]
[ \bar{X} = \frac{701}{10} ]
[ \bar{X} = 70.1 ]
Now, let's calculate the sum of squares of deviations from the mean:
[ \sum{(X – \bar{X})^2} = (81 – 70.1)^2 + (32 – 70.1)^2 + (61 – 70.1)^2 + (72 – 70.1)^2 + (74 – 70.1)^2 + (75 – 70.1)^2 + (76 – 70.1)^2 + (71 – 70.1)^2 + (84 – 70.1)^2 + (85 – 70.1)^2 ]
[ \sum{(X – \bar{X})^2} = 113.61 + 1218.01 + 92.41 + 2.89 + 14.44 + 27.04 + 37.21 + 1.21 + 170.84 + 225.00 ]
[ \sum{(X – \bar{X})^2} = 1892.66 ]
Now, let's plug the values into the standard deviation formula:
[ \sigma = \sqrt{\frac{1892.66}{10}} ]
[ \sigma = \sqrt{189.266} ]
[ \sigma ≈ 13.75 ]
Therefore, the standard deviation of the given dataset is approximately 13.75.
4. Summary
5. Conclusion
In conclusion, the range and standard deviation of the given dataset have been calculated. These measures provide insights into the variability and dispersion of data points around the mean. The range indicates the difference between the highest and lowest values, while the standard deviation measures the average deviation of individual data points from the mean. These measures are useful for understanding the spread and distribution of numerical data.