In a group of buffaloes and ducks, the number of legs are 24 more than twice the number of heads. What is the number of buffaloes in the group?

Let’s denote the number of buffaloes as \(b\) and the number of ducks as \(d\).

Since each buffalo has 4 legs and each duck has 2 legs, the total number of legs in the group is \(4b + 2d\). The total number of heads, which is also the total number of animals, is \(b + d\).

According to the problem, the number of legs is 24 more than twice the number of heads. Therefore, we can write the equation:

\[4b + 2d = 2(b + d) + 24\]

Simplifying this equation:

\[4b + 2d = 2b + 2d + 24\]
\[2b = 24\]
\[b = 12\]

So, there are 12 buffaloes in the group.