The ratio of quantity of water in fresh fruits to that of dry fruits is 7 : 2. If 400 kg of dry fruits contain 50 kg of water then find the weight of the water in same fruits when they were fresh?
The ratio of quantity of water in fresh fruits to that of dry fruits is 7 : 2. If 400 kg of dry fruits contain 50 kg of water then find the weight of the water in same fruits when they were fresh?
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Let’s denote the weight of water in the fresh fruits as \(W_f\) kg and the total weight of the fresh fruits as \(F\) kg.
According to the given information, the ratio of the quantity of water in fresh fruits to that of dry fruits is 7:2. This means that for every 7 kg of water in fresh fruits, there are 2 kg of water in dry fruits.
We know that 400 kg of dry fruits contain 50 kg of water. Using the given ratio, we can find the weight of water in the fresh fruits:
\[ \frac{W_f}{50 \text{ kg}} = \frac{7}{2} \]
Solving for \(W_f\):
\[ W_f = 50 \text{ kg} \times \frac{7}{2} = 175 \text{ kg} \]
Therefore, the weight of the water in the same fruits when they were fresh is 175 kg.