With a two digit prime number, if 18 is added, we get another prime number with digits reversed. How many such numbers are possible?
(a) 2
(b) 3
(c) 0
(d) 1
With a two digit prime number, if 18 is added, we get another prime number with digits reversed. How many such numbers are possible? (a) 2 (b) 3 (c) 0 (d) 1
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Let the number be \(10 x+y\).
According to condition
\[
\begin{aligned}
& 10 x+y+18=10 y+x \\
& y-x=2
\end{aligned}
\]
Numbers which are satisfying this equation \(02,13,24,35,46,57,68,79,80\) where 13 and 79 are prime numbers.
Therefore, Correct option is (a) 2.