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Home/ Questions/Q 54209
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Ramakant Sharma
Ramakant SharmaInk Innovator
Asked: May 9, 20242024-05-09T11:54:13+05:30 2024-05-09T11:54:13+05:30In: Psychology

Compute range and standard deviation for the following data : 2, 10, 7, 6, 5, 14, 12, 7, 8, 1.

For the following data, determine the range and standard deviation: 2, 10, 7, 6, 5, 14, 12, 7, 8, 1.

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    1. Ramakant Sharma Ink Innovator
      2024-05-09T11:55:08+05:30Added an answer on May 9, 2024 at 11:55 am

      1. Range

      The range of a dataset is the difference between the highest and lowest values in the dataset. It provides a measure of the spread or variability of the data.

      To compute the range for the given dataset:

      1. Arrange the dataset in ascending order:
        1, 2, 5, 6, 7, 7, 8, 10, 12, 14

      2. Calculate the difference between the highest and lowest values:
        Range = Maximum value – Minimum value
        Range = 14 – 1
        Range = 13

      Therefore, the range of the given dataset is 13.

      2. Standard Deviation

      The standard deviation measures the average distance of each data point from the mean of the dataset. It provides a measure of the dispersion or variability of the data points around the mean.

      To compute the standard deviation for the given dataset:

      1. Calculate the mean of the dataset:
        Mean = (2 + 10 + 7 + 6 + 5 + 14 + 12 + 7 + 8 + 1) / 10
        Mean = 72 / 10
        Mean = 7.2

      2. Calculate the squared differences between each data point and the mean:
        (2 – 7.2)^2 = 29.16
        (10 – 7.2)^2 = 7.84
        (7 – 7.2)^2 = 0.04
        (6 – 7.2)^2 = 14.44
        (5 – 7.2)^2 = 4.84
        (14 – 7.2)^2 = 46.24
        (12 – 7.2)^2 = 23.04
        (7 – 7.2)^2 = 0.04
        (8 – 7.2)^2 = 0.64
        (1 – 7.2)^2 = 38.44

      3. Calculate the sum of the squared differences:
        29.16 + 7.84 + 0.04 + 14.44 + 4.84 + 46.24 + 23.04 + 0.04 + 0.64 + 38.44 = 164.36

      4. Divide the sum of squared differences by the number of data points (N) to get the variance:
        Variance = Sum of squared differences / N
        Variance = 164.36 / 10
        Variance = 16.436

      5. Take the square root of the variance to get the standard deviation:
        Standard Deviation = √Variance
        Standard Deviation = √16.436
        Standard Deviation β‰ˆ 4.06

      Therefore, the standard deviation of the given dataset is approximately 4.06.

      Conclusion

      In summary, for the given dataset:

      • Range = 13
      • Standard Deviation β‰ˆ 4.06

      These measures provide insights into the spread and variability of the data, helping to understand the distribution of values and assess the consistency or dispersion of the dataset.

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