If * means adding six times of the second number into the first number, then find the value of \(\left(1^{*} 2\right)^{*} 3\).
If * means adding six times of second number into first number, then find the value of \(\left(1^{*} 2\right)^{*} 3\).
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To solve the expression \(\left(1^{*} 2\right)^{*} 3\), where \(^*\) means adding six times the second number to the first number, we follow the defined operation step by step.
Step 1: Solve \(1^{*} 2\)
According to the operation definition, \(1^{*} 2\) means:
\[
1 + 6 \times 2 = 1 + 12 = 13
\]
So, \(1^{*} 2 = 13\).
Step 2: Solve \(\left(1^{*} 2\right)^{*} 3\)
Now we need to apply the result from Step 1 into the next part of the expression with 3:
\[
13^{*} 3 = 13 + 6 \times 3 = 13 + 18 = 31
\]
Therefore, the value of \(\left(1^{*} 2\right)^{*} 3\) is \(\boldsymbol{31}\).