In covering a distance of 30 km Amit takes 2 hours more than Suresh, If Amit doubles his speed, he would take 1 hour less than Suresh. Amit’s speed is :

– Distance covered by both Amit and Suresh is 30 km.
– Amit takes 2 hours more than Suresh to cover this distance.
– If Amit doubles his speed, he takes 1 hour less than Suresh.

Let’s denote:
– Amit’s original speed as \(s\) km/h.
– Suresh’s time to cover 30 km as \(t\) hours.

From the first condition, Amit’s time to cover 30 km is \(t + 2\) hours, so we can write Amit’s speed as:

\[ s = \frac{30}{t + 2} \]

From the second condition, if Amit doubles his speed, his time to cover 30 km becomes \(t – 1\) hours. So, we can write:

\[ 2s = \frac{30}{t – 1} \]

Substituting the expression for \(s\) from the first equation into the second equation:

\[ 2 \times \frac{30}{t + 2} = \frac{30}{t – 1} \]

Cross-multiplying:

\[ 60(t – 1) = 30(t + 2) \]

Expanding:

\[ 60t – 60 = 30t + 60 \]

Rearranging:

\[ 30t = 120 \]

\[ t = 4 \text{ hours} \]

Now, we can find Amit’s original speed:

\[ s = \frac{30}{t + 2} = \frac{30}{4 + 2} = \frac{30}{6} = 5 \text{ km/h} \]

So, Amit’s original speed is 5 km/h.